program to check the number is armstrong or not

#include<iostream.h>
#include<conio.h>
#include<stdio.h>
#include<math.h>
void main()
{
    int i,j,n,num=0;
    clrscr();
    cout<<"\nenter the number ";
    cin>>n;
    int m=n;
    while((m%10!=0)||(m/10!=0))
    {
        num=num+pow((m%10),3);
           //    cout<<"\n"<<num;
           //    getch();
        m=m/10;
    }
    cout<<"  "<<num;
    if(num==n)
    {
        cout<<"\nthe number is armstrong ";
    }
    else
    {
        cout<<"\nthe number is not armstrong ";
    }
    getch();
}

OUTPUT: